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Hi :)
Sounds like a good fail-safe, so that users are not bound by rigid
restrictions but the displayed figures are always consistently correct.

I suspect that you can even enter much shorter numbers for dates within the
year, such as;
12.31
getting corrected to;
2014.12.31
I'm not sure if you can also drop the month, if it's within the same month,
and just type
31
to get the same result but even a little less typing can make a
difference.
Regards from
Tom :)




On 28 December 2014 at 04:43, Brian Barker <b.m.barker@btinternet.com>
wrote:

At 02:29 28/12/2014 +0000, Conly Honly Donly wrote:

A quick recap: I was looking for the YYYY.MM.DD format. The user inputs
it as it looks, e.g. 2015.01.01. (LibreOffice Calc should recognise it as a
date.)
Here:
Tools -> Options -> Language Settings -> Languages -> Date acceptance
patterns
I don't know how this should be set. I tried YYYY.MM.DD. This did not
work. (with the semicolon) I tried Y.M.D. This worked. (with the semicolon)
Here:
Format -> Cells -> Numbers -> Format code
I must use YYYY.MM.DD, not Y.M.D.

What led to this inconsistent format? I am interested in the technical
reasons behind. I think that it will be consistent if a user is allowed to
type the same YYYY.MM.DD format code in both places to get what she or he
wants.


I'm guessing here, but surely there are different requirements in the two
places? In the cell formatting, you are indicating exactly the format you
require - so you are choosing the year to appear as YYYY, not YY, for
example. But the acceptance pattern is more general: you are merely showing
that you want year-dot-month-dot-day to be a format automatically
interpreted as a date. With Y.M.D as an acceptance pattern, can you not
enter the forthcoming New Year's Day (for example) as 2015.01.01, 2015.1.1,
15.01.01, and many other forms - but have all interpreted correctly and
displayed in the cell itself in the cell's format - as 2015.01.01 in your
case?

I trust this helps.

Brian Barker



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