Re: [libreoffice-users] Calc: Average value, multiple conditions

Johnny Rosenberg wrote:
> I have a spreadsheet with quite a lot of values and text.
> Column C: Name.
> Column D: Date.
> Column H: Values (integers, currently in the range of 176 to 605).
>
> R1: A specific name that matches many of the rows of column C.
> P2: Start date.
> Q2: End date.
>
> I tried this:
> {=SUM(($C$2:$C$1001=R$1)*($D$2:$D$1001>=$P2)*($D$2:$D$1001<$Q2)*$H$2:$H$1001)}
> Works great. Gives 29072 in my specific spreadsheet. Expected value: 29072.
>
> Now, I changed to:
> {=AVERAGE(($C$2:$C$1001=R$1)*($D$2:$D$1001>=$P2)*($D$2:$D$1001<$Q2)*$H$2:$H$1001)}
> Result: 52.29.
> Expected value: Somewhere around 450.
>
> Was I just too quick to assume that AVERAGE can be used in the same way as SUM?
Kind regards Johnny Rosenberg ジョニー・ローゼンバーグ

     The SUM is exactly that: the total of the numbers that are 
generated from the given rows. An AVERAGE is the sum divided by how many 
numbers were generated.
      Comment: With the sum being 29072 and expected average of 450, 
there had to be about 65 numbers that your array added. With the sum 
being 29072 and actual average of 52.29, there was about 556 numbers. Do 
you have any idea how many numbers would be created by your array?
      I am a little curious though. Which number is closer: 65 or 556?

--Dan


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